Leetcode [1085] - Sum of Digits in the Minimum Number (Java Solution)

Leetcode [1085] - Sum of Digits in the Minimum Number (Java Solution)
Category: Easy
What is used: Arrays, Linear Search

Question

Given an array A of positive integers, let S be the sum of the digits of the minimal element of A.
Return 0 if S is odd, otherwise return 1.

Example 1:

Input: [34,23,1,24,75,33,54,8]
Output: 0
Explanation: The minimal element is 1, and the sum of those digits is S = 1 which is odd, so the answer is 0.

Example 2:

Input: [99,77,33,66,55]
Output: 1
Explanation: The minimal element is 33, and the sum of those digits is S = 3 + 3 = 6 which is even, so the answer is 1.

Note:

1. 1 <= A.length <= 100
2. 1 <= A[i].length <= 100

Solution

This is a easy problem. The 3 steps to solve this problem should be:
1. Find the minimum of the array - I used Linear Search O(n)
2. Find the sum of the minimum number - The standard way of modulo 10 and divide by 10. O(n)
3. Check if sum is odd - Simple if-else statement

```
class Solution {
public int sumOfDigits(int[] A) {

    //Find minimum
    int min = Integer.MAX_VALUE;
    for(int i = 0; i < A.length; i++){
        if(A[i] < min){
            min = A[i];
        }
    }
    int n = 0;
    int sum = 0;
    
    //Sum of minimum
    while(min > 0){
        n = min % 10;
        sum = sum + n;
        min = min / 10;
    }
    
    //Odd-Even Check
    if(sum % 2 != 0){
        return 0;
    }else{
        return 1;
    }
}

Time complexity:

The time complexity of this code is O(n)

Submission Details:

Runtime: 0 ms, faster than 100.00% of Java online submissions for Sum of Digits in the Minimum Number.
Memory Usage: 34.3 MB, less than 100.00% of Java online submissions for Sum of Digits in the Minimum Number.